Question 16 Exercise 4.2

Solutions of Question 16 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Insert five arithmetic means between $5$ and $8$ and show that their sum is five times the arithmetic mean between $5$ and $8$.

Let $A_1, A_2, A_3, A_4, A_5$ be five arithmetic means between $5$ and $8$. Then $5, A_1, A_2, A_3, A_4, A_5, 8$ are in A.P, where $$a_1=5 \text{ and } a_7=8.$$ As we have $$\begin{align}&a_7=a+6d\\ \implies &8=5+6d\\ \implies &6d=8-5\\ \implies &d=\dfrac{3}{6}=\dfrac{1}{2}. \end{align}$$ Now $$\begin{align} A_1&=a+d=5+\dfrac{1}{2}=\dfrac{11}{2},\\ A_2&=a+2 d=5+2 \cdot \dfrac{1}{2}=6,\\ A_3&=a+3 d=5+3 \cdot \dfrac{1}{2}=\dfrac{13}{2},\\ A_4&=a+4 d=5+4 \cdot \dfrac{1}{2}=7,\\ A_5&=a+5 d=5+5 \cdot \dfrac{1}{2}=\dfrac{15}{2}.\end{align}$$ Hence $\dfrac{11}{2},6,\dfrac{13}{2},7, \dfrac{15}{2}$ are five A.Ms between $5$ & $8$.

Now $$\begin{align}A_1&+A_2+A_3+A_4+A_5 \\ &=\dfrac{11}{2}+6+\dfrac{13}{2}+7+\dfrac{15}{2}\\ &=\dfrac{11}{2}+\dfrac{12}{2}+\dfrac{13}{2}+\dfrac{14}{2}+\dfrac{15}{2}\\ &=\dfrac{11+12+13+14+15}{2}\\ &=\dfrac{65}{2}---(i)\end{align}$$ Let $A$ be arithmetic mean between 5 and 8. Then $$A=\dfrac{a+b}{2}=\dfrac{5+8}{2}=\dfrac{13}{2}$$ Multiplying both side of the arithmetic mean by 5 , we get
$$5 A=\dfrac{65}{2}---(ii)$$ From (i) and (ii), we get
$$\begin{align}A_1+A_2+A_3+A_4+A_5=5A.\end{align}$$ Hence sum of five A.Ms between 5 and 8 is five times their A.M.

< Question 15 Question 17 >