Question 2, Exercise 2.1

Solutions of Question 2 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2

Let A=[2−5130−4], B=[1−2−30−15] and C=[01−20−1−1]. Find 2A+3B−4C.

Solution

Given: A=[2−5130−4], B=[1−2−30−15] and C=[01−20−1−1].

Then 2A=[4−10260−8], 3B=[3−6−90−315], 4C=[04−80−4−4]. 2A+3B−4C=[4−10260−8]+[3−6−90−315]−[04−80−4−4]=[4+3−10−62−96+00−3−8+15]−[04−80−4−4]=[7−16−76−37]−[04−80−4−4]=[7−0−16−4−7+86−0−3+47+4]=[7−2016111]

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