Question 1 Review Exercise 5
Solutions of Question 1 of Review Exercise 5 of Unit 05: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.
Question 1
Chose the correct option.
i. If tn=6n+5 then tn+1=
- (a) 6n−1
- (b) 6n+11
- (c) 6n+6
- (d) 6n−5
(b): 6n+11
ii. The sum to infinity of the series: 1+23+632+1033+1434+…
- (a) 6
- (b) 2
- (c) 3
- (d) 4
©: 3
iii. Sum the series:1+2.2+3.22+⋯+100.2′′
- (a) 99.2100
- (b) 100.2100
- (c) 99.2100+1
- (d) 1000.2100
©: 99.2100+1
iv. The nth term of the series: 1.2+2.3+3.4+…
- (a) n2−n
- (b) n2+n
- (c) n2
- (d) None of these
(b): n2+n
v. Sum of n terms of the series whose nth term is 1+2n
- (a) n⋅2n−1
- (b) (n+1)+2n+1
- (c) n+2(2n−1)
- (d) None of these
©: n+2(2n−1)
vi. Evaluate Σ(3+2r), where r=1,2,3,…,10
- (a) 2051
- (b) 2049
- (c) 2076
- (d) 1052
©: 2076
vii. What is the n term of the series: 1+1+22+1+2+33+…
- (a) n+12
- (b) n(n+1)2
- (c) n2−(n+1)
- (d) (n+1)(2n+3)2
(a): n+12
viii. Sum of n terms of the series 13+33+53+73+…
- (a) n2(2n2−1)
- (b) 2n3+3n2
- (c) n3(n−1)
- (d) n3+8n+4
(a): n2(2n2−1)
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