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Question 3, Exercise 2.6
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\begin{align*} \frac{19}{4}z& = -\frac{63}{4}\\ \Rightarrow z& = -\frac{63}{19}\end{align*} From the second row, we have: \begin{align*} &- 2y - 3z = 3\\ \Rightarrow &-2y - 2(-\frac{63}{19}) = 3 \\ \Rightarrow &-2y = -\frac{132}{19} \\ \Rightarrow &y = \frac{66}{19}\end{align*} Finally, from the first row, we have: \
Question 4, Exercise 2.6
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\frac{3}{2}x_2 + \frac{7}{2}x_3 = \frac{1}{2}\\ \Rightarrow &x_1 = \frac{1}{2} + \frac{3}{2}\frac{2}{11}\\ \Rightarrow & x_1= \frac{1}{2} + \frac{3}{11}\\ \Rightarrow & x_1= \frac{17}{22}\end{align*} Thus, the general solution i
Question 1, Exercise 2.5
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6 \\ 0 & 2 & 4 \end{array}\right]\quad R_1 \leftrightarrow R_3 \\ \sim & \text{R} \left[\begin{array}{ccc}